20x^2-5x+1=0

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Solution for 20x^2-5x+1=0 equation:


Simplifying
20x2 + -5x + 1 = 0

Reorder the terms:
1 + -5x + 20x2 = 0

Solving
1 + -5x + 20x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
20 the coefficient of the squared term: 

Divide each side by '20'.
0.05 + -0.25x + x2 = 0

Move the constant term to the right:

Add '-0.05' to each side of the equation.
0.05 + -0.25x + -0.05 + x2 = 0 + -0.05

Reorder the terms:
0.05 + -0.05 + -0.25x + x2 = 0 + -0.05

Combine like terms: 0.05 + -0.05 = 0.00
0.00 + -0.25x + x2 = 0 + -0.05
-0.25x + x2 = 0 + -0.05

Combine like terms: 0 + -0.05 = -0.05
-0.25x + x2 = -0.05

The x term is -0.25x.  Take half its coefficient (-0.125).
Square it (0.015625) and add it to both sides.

Add '0.015625' to each side of the equation.
-0.25x + 0.015625 + x2 = -0.05 + 0.015625

Reorder the terms:
0.015625 + -0.25x + x2 = -0.05 + 0.015625

Combine like terms: -0.05 + 0.015625 = -0.034375
0.015625 + -0.25x + x2 = -0.034375

Factor a perfect square on the left side:
(x + -0.125)(x + -0.125) = -0.034375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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